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samir sawantSubject: Applying XSL on dynamic XML input
Author: samir sawant
Date: 09 Feb 2005 05:46 PM
I have an XML file say as below:

<region>
<row>
<field1>017814100</field1>
<field2>178141</field2>
<field3>SWITCH</field3>
<field4>006</field4>
<field5>000011</field5>
<field6>109.36</field6>
<field7>74.28</field7>
</row>
<row>
<field1>307429600</field1>
<field2>3074296</field2>
<field3>CLP,RTG</field3>
<field4>006</field4>
<field5>000011</field5>
<field6>168.59</field6>
<field7>114.51</field7>
</row>
.....
.....
</region>

I want this XML file to be converted into PDF format
in 2 columns as below:

H1 H2 H3 H4 H5 H6 H7 H1 H2 H3 H4 H5 H6 H7
-- -- -- -- -- -- -- -- -- -- -- -- -- --
-- -- -- -- -- -- -- -- -- -- -- -- -- --

Where H1 to H7 are field headings and -- is record
element. The flow of records is down and then across.

Wait..The main question or Problem is ahead....

My XML input can change, It means it will still have 7
fields but few fields marked as 'NIL' like as below.
In below XML , field 4 and 7 are marked as 'NIL'

<region>
<row>
<field1>017814100</field1>
<field2>178141</field2>
<field3>SWITCH</field3>
<field4>NIL<field4>
<field5>000011</field5>
<field6>109.36</field6>
<field7>NIL</field7>
</row>
<row>
<field1>307429600</field1>
<field2>3074296</field2>
<field3>CLP,RTG</field3>
<field4>NIL</field4>
<field5>000011</field5>
<field6>168.59</field6>
<field7>NIL</field7>
</row>
.....
.....
</region>


In this case my PDF output should be as below without
field4 and field7:


H1 H2 H3 H5 H6 H1 H2 H3 H5 H6
-- -- -- -- -- -- -- -- -- --
-- -- -- -- -- -- -- -- -- --


Any of my field can be 'NIL' (It will be consistently NIL throughout the XML document). The PDF output should be properly spaced in 2 columns irrespective of the number of non NIL field elements.

Thanks,

Samir


DocumentXML_XSL(2).doc

Posttop
Ivan PedruzziSubject: Applying XSL on dynamic XML input
Author: Ivan Pedruzzi
Date: 10 Feb 2005 12:11 AM
Samir,

If the column number is potentially variable (between 0 and 7)
for each row you need to replicate the header each row or have
the hedaer with all columns at the top

The following XSLT should get you started
Hope this helps
Ivan


<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml"/>


<xsl:template match="/">

<fo:root>
<fo:layout-master-set>
<fo:simple-page-master master-name="default-master">
<fo:region-body/>
</fo:simple-page-master>
</fo:layout-master-set>

<fo:page-sequence master-reference="default-master">
<fo:flow flow-name="xsl-region-body">

<fo:block margin-left="10pt">My Title</fo:block>
<fo:block>

<fo:table table-layout="fixed" width="100%" margin-left="10pt" margin-right="10pt">
<xsl:for-each select="region/row[position() &lt; 3]/*">
<fo:table-column/>
</xsl:for-each>
<fo:table-body>

<xsl:for-each select="region/row[position() mod 2 = 1]">

<fo:table-row>
<xsl:apply-templates select="* | following-sibling::row[1]/*" mode="header"/>
</fo:table-row>

<fo:table-row height="8pt">
<xsl:apply-templates select="* | following-sibling::row[1]/*" mode="cell"/>
</fo:table-row>

</xsl:for-each>

</fo:table-body>
</fo:table>
</fo:block>
</fo:flow>
</fo:page-sequence>
</fo:root>
</xsl:template>

<xsl:template match="*" mode="header">
<fo:table-cell>
<fo:block font-style="bold">
<xsl:if test=".!='NIL'">
<xsl:value-of select="concat('H', translate(local-name(), 'field',''))"/>
</xsl:if>
</fo:block>
</fo:table-cell>
</xsl:template>

<xsl:template match="*" mode="cell">
<fo:table-cell>
<fo:block font-size="8pt">
<xsl:if test=".!='NIL'">
<xsl:value-of select="."/>
</xsl:if>
</fo:block>
</fo:table-cell>
</xsl:template>
</xsl:stylesheet>

 
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