[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to efficiently obtain the first 10 records of
On 19.07.2023 17:16, Roger L Costello costello@xxxxxxxxx wrote:
obtain the first 10 <record> elements.
processor is iterating over all 2 million <record> elements. Yes? How to write the XSLT code so that the XSLT processor stops iterating upon processing the first 10 <record> elements? Using XSLT 3.0 and Saxon EE with streaming you could use e.g. <xsl:mode streamable="yes"/> <xsl:template match="/"> B <xsl:copy-of select="Document/record[position() le 10]"/> </xsl:template> I am not sure whether you need an explicit <xsl:mode streamable="yes"/> <xsl:template match="/"> B <xsl:iterate select="Document/record"> B B B <xsl:copy-of select="."/> B B <xsl:if test="position() eq 10"> B B B B <xsl:break/> B B </xsl:if> B </xsl:iterate> </xsl:template>
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