[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

XSLT 2 and XSLT 3: Best Way To Get Set of Unique Docs

Subject: XSLT 2 and XSLT 3: Best Way To Get Set of Unique Docs for A Set of Elements
From: "Eliot Kimber ekimber@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 5 Mar 2019 19:07:57 -0000
 XSLT 2 and XSLT 3: Best Way To Get Set of Unique Docs
Given the variable $links that is a sequence of element()s where the elements
could be from different documents, what is the best way to get the set of
unique documents?

I need an XSLT 2 answer but an XSLT 3 answer would also be useful.

I feel like there's an obvious solution I'm overlooking but the only thing I
can think of is to compare the document-uri() values of all the elements:

    <xsl:variable name="topicURIs" as="xs:string*"
      select="distinct-values(for $e in $links return
document-uri(root($e)))"
    />
    <xsl:variable name="topics" as="document-node()*"
        select="
        for $uri in $topicURIs
        return root(($links[document-uri(root(.)) eq $uri])[1])
        "
    /> o;?

This works but seems unnecessarily complicated.

Thanks,

Eliot
--
Eliot Kimber
http://contrext.com

Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.