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Re: Is there a way to use character-map to do replace

Subject: Re: Is there a way to use character-map to do replacements in a string ?
From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 19 Mar 2019 16:23:35 -0000
Re:  Is there a way to use character-map to do  replace
On 19.03.2019 16:15, Christophe Marchand cmarchand@xxxxxxxxxx wrote:
I have a variable :
<xsl:variable name="content" as="xs:string" select='EC'/>

I want to transform special caracters according to a character-map
definition (I think it's much easier to maintain) :
 B  <xsl:character-map name="cm">
 B B B  <xsl:output-character character="E" string="oe"/>
 B B B  <xsl:output-character character="C" string="ss"/>
 B  </xsl:character-map>

Something like
<xsl:variable name="escaped" as="xs:string"
select="escape-according-tocharacter-map($content, 'cm')"/>

Is there a way to do it with XSLT 3.0 ?

The serialize function from XPath 3 allows you to supply a character map
but in XPath 3.1 map syntax

serialize($content, map { 'method' : 'text', 'use-character-maps' : map
{ 'E' : 'oe', 'C' : 'ss' }})

I am currently not sure there is a way to reference a map in the
stylesheet, other than perhaps using

  map:join(document('')/*/xsl:character-map[@name =
'cm']/xsl:output-character/map-entry(@character, @string))

instead of the hardcoded map { 'E' : 'oe', 'C' : 'ss' }}

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