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Re: XPath - accessing nodes with a namespace with no

Subject: Re: XPath - accessing nodes with a namespace with no prefix
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Fri, 04 Dec 2009 17:17:25 -0500
Re:  XPath - accessing nodes with a namespace with no
At 2009-12-04 17:04 -0500, Philip Vallone wrote:
This is a pure xpath question.

Which is frequently asked.


Suppose I have a namespace declaration like this:

<organizations version="1.0" xmlns="http://www.imsglobal.org/xsd/imscp_v1p1">

The namespace does not have a prefix.

Right, but the element node in the tree has the namespace in the expanded name.


I want to use local-name() to access the nodes

Why? That would be improper. You want to use qualified names representing expanded names to access the node.


but not sure how. For example, how do I access a path like this:

XPATH:

/organizations/organization/title[2]/title

In an XSLT 1 or XSLT 2 stylesheet:


xmlns:ims="http://www.imsglobal.org/xsd/imscp_v1p1"
...
/ims:organizations/ims:organization/ims:title[2]/ims:title

XML:
<organizations version="1.0" xmlns="http://www.imsglobal.org/xsd/imscp_v1p1">
<organization>
<title>SCORM 2004 4th Edition Manifest Basics Content Example 1.0</title>
...

The expanded name in the stylesheet must match the expanded name in the XML data. The qualified name in the stylesheet can be different than the qualified name in the XML data. The qualified name in the stylesheet cannot use the default namespace in XSLT 1.


In XSLT 2 you can use xpath-default-namespace= to support unprefixed names in XPath, but I've come to the conclusion it isn't helpful when more than one input namespace is in use.

I hope this helps.

. . . . . . . . . . . Ken

--
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