RE: Help with an xsl:if

Of course it should be != rather than =! - but I wonder if that was really
your problem?

You can also write

<xsl:value-of select="crosslist[. != 'none']"/>

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Michelle Tarby [mailto:tarbymm@xxxxxxxxxxx] 
> Sent: 08 May 2008 19:03
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Help with an xsl:if
> 
> I can't figure out what I'm doing wrong with this statement. 
> If I take out the xsl:if, everything displays properly, but 
> I'd like to only display crosslist if there's something other 
> than none as a value:
> 
> <xsl:for-each select="fll/class">
> <xsl:value-of select="number"/>.
> <xsl:value-of select="title"/>
> (<xsl:value-of select="credits"/>)
> <xsl:if test="crosslist=!'none'">
> <xsl:value-of select="crosslist" />
> </xsl:if>
> <xsl:value-of select="prereq"/><br />
> <xsl:value-of select="description"/><br /><br /> </xsl:for-each>
> 
> Any suggestions would be appreciated.
> 
> --
> Michelle Tarby
> Director of Web Services
> Information Technology
> Le Moyne College
> http://www.lemoyne.edu
> tarbymm@xxxxxxxxxxx
> *****************************
> "That's the beauty of tomorrow. There is no such thing as a 
> setback. The lessons I learn today I will apply tomorrow, and 
> I will be better."
> - Tiger Woods