Re: XSL/XPath to generate a list of ancestors?

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Subject: Re: XSL/XPath to generate a list of ancestors?
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Mon, 12 May 2008 19:15:26 +0200

Nathan Potter wrote:

On May 12, 2008, at 10:05 AM, Martin Honnen wrote:
Nathan Potter wrote:
I tried this:
     <xsl:template match="*" name="fullNameWorker" mode="fullName">
        <xsl:if test="generate-id(.)!=generate-id(/)">
You have a template for element nodes (match="*") so why do you test
  generate-id(.) != generate-id(/)
? An element (.) is never a root node (/).
Because the template recursively ascends the document I need to test that I have arrived at the top.

But your template with match="*" is never processed for the root node which is match="/". If anything makes sense then generate-id(.) != generate-id(/*) as that compares the matched element to the root element (which is different from the root node).

--

	Martin Honnen
	http://JavaScript.FAQTs.com/

Current Thread
RE: XSL/XPath to generate a list of ancestors?, (continued) Michael Kay - 12 May 2008 16:14:18 -0000 Nathan Potter - 12 May 2008 16:54:53 -0000 Martin Honnen - 12 May 2008 17:06:23 -0000 Nathan Potter - 12 May 2008 17:11:40 -0000 Martin Honnen - 12 May 2008 17:15:48 -0000 <= Nathan Potter - 12 May 2008 17:23:56 -0000

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