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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Output sorted XHTML table for a subset of elements
 Another v1.0 example, but without extensions:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="Windows-1252" />
<xsl:template match="/users">
<html>
<body>
<table>
<tr>
<xsl:for-each select="user">
<xsl:sort select="lines" data-type="number"
order="descending"/>
<xsl:if test = "lines > 25">
<td><xsl:value-of select="@name"
/>(<xsl:value-of select="lines" />)</td>
</xsl:if>
<xsl:if test="position() mod 5 = 0">
<xsl:text disable-output-escaping =
"yes">
</tr>
</xsl:text>
<xsl:text disable-output-escaping =
"yes"><tr>
</xsl:text>
</xsl:if>
</xsl:for-each>
</tr>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
The </tr><tr> bit is rather ugly, but I find the test="position() mod
5 = 0" rather elegant.
Cheers
Erik
On Sun, May 25, 2008 at 12:53 PM, Martin Honnen <Martin.Honnen@xxxxxx> wrote:
>
> Steven Davies wrote:
>
>> I know my sample data was a bit small but there are a lot more nodes in
>> my actual data set. Here's an attempt at a better example:
>>
>> <users>
>> <user name="alf"><lines>7</lines></user>
>> <user name="bert"><lines>78</lines></user>
>> <user name="charlie"><lines>731</lines></user>
>> <user name="derek"><lines>62</lines></user>
>> <user name="edward"><lines>93</lines></user>
>> <user name="fred"><lines>823</lines></user>
>> <user name="george"><lines>42</lines></user>
>> <user name="harry"><lines>28</lines></user>
>> <user name="ian"><lines>553</lines></user>
>> <user name="joshua"><lines>92</lines></user>
>> <user name="kevin"><lines>108</lines></user>
>> <user name="luke"><lines>192</lines></user>
>> </users>
>>
>> should give the output:
>>
>> <table>
>> <tr>
>> <td>fred (823)</td>
>> <td>charlie (731)</td>
>> <td>ian (553)</td>
>> <td>luke (192)</td>
>> <td>kevin (108)</td>
>> </tr>
>> <tr>
>> <td>edward (93)</td>
>> <td>joshua (92)</td>
>> <td>bert (78)</td>
>> <td>derek (62)</td>
>> <td>george (42)</td>
>> </tr>
>> <tr>
>> <td>harry (28)</td>
>> </tr>
>> </table>
>
> Here is an XSLT 1.0 stylesheet making use of exslt:node-set:
>
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:exsl="http://exslt.org/common"
> exclude-result-prefixes="exsl"
> version="1.0">
>
> <xsl:output method="html" indent="yes"/>
>
> <xsl:param name="cols" select="5"/>
>
> <xsl:param name="min-lines" select="25"/>
>
> <xsl:template match="/">
> <html>
> <head>
> <title>Example</title>
> </head>
> <body>
> <xsl:apply-templates select="users"/>
> </body>
> </html>
> </xsl:template>
>
> <xsl:template match="users">
> <xsl:variable name="sorted-users-rtf">
> <data>
> <xsl:for-each select="user[lines > $min-lines]">
> <xsl:sort select="lines" data-type="number" order="descending"/>
> <xsl:copy-of select="."/>
> </xsl:for-each>
> </data>
> </xsl:variable>
> <xsl:variable name="sorted-users" select="exsl:node-set($sorted-users-rtf)/data/user"/>
> <table>
> <tbody>
> <xsl:apply-templates select="$sorted-users[position() mod $cols = 1]" mode="row"/>
> </tbody>
> </table>
> </xsl:template>
>
> <xsl:template match="user" mode="row">
> <tr>
> <xsl:apply-templates select=". | following-sibling::user[position() < $cols]" mode="cell"/>
> </tr>
> </xsl:template>
>
> <xsl:template match="user" mode="cell">
> <td>
> <xsl:value-of select="concat(@name, ' (', lines, ')')"/>
> </td>
> </xsl:template>
>
> </xsl:stylesheet>
>
> I think libXSLT supports exsl:node-set.
>
>
> --
>
> Martin Honnen
> http://JavaScript.FAQTs.com/
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