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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: InnerElement attribute needs to be set for parent
You could use the modified identity stylesheet, as shown below:
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="propertyList">
<propertyList>
<xsl:for-each select="property">
<xsl:attribute name="{@name}">
<xsl:value-of select="@value" />
</xsl:attribute>
</xsl:for-each>
</propertyList>
</xsl:template>
PS: Your input XML is not well formed ...
On Sat, May 10, 2008 at 12:40 PM, Arulraj <p_arulraj@xxxxxxxxx> wrote:
> Hello,
>
> i have the following input xml, i am using XSL for the transformation.
> <?xml version="1.0" encoding="UTF-8"?>
> <extraList jcr:primaryType="extraList" >
> <customerInfo jcr:primaryType="customerinfo">
> <propertyList>
> <property name="betriebsnummer_str" value="54321"/>
> <property name="email_str" value="test"/>
> </propertyList>
> </customerInfo>
> <info>
> <propertyList>
> <property name="yyy_str" value="123"/>
> <property name="email_str" value="yahoo.com"/>
> </propertyList>
> <info>
> </extraList>
>
> My expected output as follows:
>
> <extraList jcr:primaryType="extraList">
> <customerInfo jcr:primaryType="customerinfo">
> <propertyList betriebsnummer_str="54321" email_str="test"/>
> </customerInfo>
> <info>
> <propertyList yyy_str="123" email_str="yahoo.com"/>
> <info>
> </extraList>
>
> How to copy the attributes from the <property> name and value to <propertyList> with name as the attribute ?
>
> Please suggest to solve this.
>
> Thanks
> Regards,
> Raj
--
Regards,
Mukul Gandhi
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