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RE: Variable containing unique values

Subject: RE: Variable containing unique values
From: "Hesselberth, Jan" <Jan.Hesselberth@xxxxxxxxxxxxxxxxxx>
Date: Wed, 21 May 2008 15:53:40 +0100
RE:  Variable containing unique values
Thanks for the reply David. I'm using xslt 1 and this has solved most of
the problem. I just need to get the dates in order now.
Thanks again.
-----Original Message-----
From: David Carlisle [mailto:davidc@xxxxxxxxx]
Sent: 21 May 2008 15:36
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  Variable containing unique values

I can't remember if you use xslt 1 or 2, in xslt2

select="distinct-values(//rolloverDate)" does what you ask.

But assuming you are using xslt 1 then getting unique values is the same
as grouping, and just using one of each group.


an XML document can only have one top level element so


either matches that element (if the document element is rolloverDate) or
matches nothing. In either case the document eleemnt never has siblins
so the preceding::rolloverDate in the filter will never select anything.

You mean to select the child of the current element, so don't start with
/ which takes you to thetop of the tree:

select="rolloverDate[not(preceding::rolloverDate= current())]"/>

but note this will repeatedly look back over all earlier nodes so can be
quite slow on large sets, hence muenchian grouping.

<xsl:key name="e" match="element" use="rolloverDate"/>

	<xsl:variable name="unique-dates">
   <xsl:copy-of select="."/>


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