[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Getting first child node postion with condition
Hi, I'm a french student in training course. I make development in xslt and I encounter the following problem : My xml file : <?xml version="1.0" encoding="UTF-8"?> <tree> <leaf attrib = 'false'>Leaf1</leaf> <leaf attrib = 'true'>Leaf2</leaf> <leaf attrib = 'true'>Leaf3</leaf> </tree> When I'm in the "tree" template, I want to get the position of the first child node with the attribute "attrib" equals "true" but I don't succeed. I attempt to use the postion function but it doesn't work : leaf[@attrib = 'true'][postion()] returns the value of the first child (Leaf2) but not its position. Is there a way to to that correctly ? Cordially, Julien Flotti. _________________________________________________________________ Gagnez des pc Windows Vista avec Live.com http://www.image-addict.fr/
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