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RE: replace

Subject: RE: replace
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Tue, 12 Jun 2007 08:53:31 +0100
RE:  replace
I suspect you want select="'a'" and select="'b'".

Why are you still using XSLT 1.0, as a matter of interest? I can understand
it if you're in a constrained environment, e.g. in a browser, but if you're
using Saxon then that's clearly not the case. Doing string manipulation in
1.0 when you could be using 2.0 seems like pure masochism to me.

Michael Kay

> -----Original Message-----
> From: Charles Ohana [mailto:charles.ohana@xxxxxxxxxxxxxx] 
> Sent: 12 June 2007 03:28
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  replace
> Hello,
> I'm sorry, I know this question has been asked several times 
> but ... After searching everywhere I could not get the 
> replace function working.
> See my code below you'll see what I'm trying to accomplish. 
> All I need is a simple working example that is replacing a 
> pattern withing a value.
> Any hint would be appreciated. I'm using SAXON 6.5.5 (java 
> -jar saxon.jar)
> Thank you
> <?xml version="1.0" encoding="utf-8"?>
> <stylesheet xmlns="http://www.w3.org/1999/XSL/Transform"
>             xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>             xmlns:str="http://exslt.org/Strings" version="1.0"
>             extension-element-prefixes="str">
> <import href="functions/replace/str.replace.xsl"/>
> <xsl:template match="/">
> <xsl:call-template name="str:replace">
>    <xsl:with-param name="string" select="/root/@description" />
>    <xsl:with-param name="search" select="a" />
>    <xsl:with-param name="replace" select="b" /> 
> </xsl:call-template> </xsl:template>
> </xsl:stylesheet> 

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