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Re: XSL hold, compare, and replace param value
Subject: Re: XSL hold, compare, and replace param value
From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Date: Fri, 14 Jul 2006 21:05:57 +0530
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Hi Steve,
As Mike pointed out, this problem is best solved using Muenchian
grouping method, if you are using XSLT 1.0.
Here is a XSLT 1.0 solution based on Muenchian method:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" />
<xsl:key name="by-country" match="entry" use="country" />
<xsl:template match="/report">
<html>
<head>
<title/>
</head>
<body>
<table border="1">
<xsl:for-each select="//entry[generate-id() =
generate-id(key('by-country', country)[1])]">
<tr>
<td><xsl:value-of select="country" /></td>
</tr>
<tr>
<td>Group</td>
<td>Name</td>
<td>id</td>
</tr>
<xsl:for-each select="key('by-country', country)">
<tr>
<td><xsl:value-of select="../@type" /></td>
<td><xsl:value-of select="name" /></td>
<td><xsl:value-of select="id" /></td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
http://gandhimukul.tripod.com/
On 7/14/06, Steve Sze <steveyksze@xxxxxxxxx> wrote:
Hi Spencer and Mike
Sorry for not giving you the details of my output. Im looking to
display the title for every new country.
So, the html output will look like this:
USA
Group Name id
AAA Adel 12345
AAA Barry 12346
AAA Carl 12347
BBB Dave 12345
BBB Ethel 12346
BBB Fred 12347
EUR
Group Name id
CCC George 24567
CCC Harold 23458
CCC Jennifer 23459
Hope this helps, thanks again!
Steve
===========================================
Sample XML file
<report>
<column>name</column>
<column>country</column>
<column>group</column>
<table>
<date>07-13-2006
<group type="AAA">111111
<entry>
<name>Adel</name>
<country>USA</country>
<id>12345</id>
</entry>
<entry>
<name>Barry</name>
<country>USA</country>
<id>12346</id>
</entry>
<entry>
<name>Carl</name>
<country>USA</country>
<id>12347</id>
</entry>
</group>
<group type="BBB">111111
<entry>
<name>Dave</name>
<country>USA</country>
<id>12345</id>
</entry>
<entry>
<name>Ethel</name>
<country>USA</country>
<id>12346</id>
</entry>
<entry>
<name>Fred</name>
<country>USA</country>
<id>12347</id>
</entry>
</group>
<group type="CCC">111111
<entry>
<name>George</name>
<country>EUR</country>
<id>24567</id>
</entry>
<entry>
<name>Harold</name>
<country>EUR</country>
<id>23458</id>
</entry>
<entry>
<name>Jennifer</name>
<country>EUR</country>
<id>23459</id>
</entry>
</group>
</date>
</table>
</report>
===========================================
Hope this is what you're looking for:
When I run this XSL:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="country[parent::entry/following-sibling::entry]">
<xsl:variable name="nextCountry"
select="parent::entry/following-sibling::entry[1]/country"/>
<xsl:choose>
<xsl:when test="$nextCountry = .">
<country><xsl:apply-templates/></country>
</xsl:when>
<xsl:otherwise>
<country><xsl:value-of select="$nextCountry"/></country>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="country[not(parent::entry/following-sibling::entry)]">
<xsl:variable name="nextCountry"
select="ancestor::group/following-sibling::group[1]/entry[1]/country"/>
<xsl:choose>
<xsl:when test="$nextCountry = . or not($nextCountry)">
<country><xsl:apply-templates/></country>
</xsl:when>
<xsl:otherwise>
<country><xsl:value-of select="$nextCountry"/></country>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Against your XML above, I get Fred's Country Changing as he is the
only one who's next country differs,,, Am I reading you correctly?
Spencer Tickner
On 7/13/06, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > I have a problem holding on to a param or variable value in xslt.
> > Setting it Globally or Locally.
> >
> > How can I hold onto the country value? Compare to the next
> > value, if country is diff. then replace the value for that
> > param with the next country value?
>
> Please take a step back. Try to describe the problem: what's the input,
> what's the required output?
>
> It looks to me as if you are trying to code a solution using ideas learned
> from other programming languages, which might not be the right way to tackle
> the problem in XSLT.
>
> Michael Kay
> http://www.saxonica.com/
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