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Re: How to use document() of doc() function with copy

Subject: Re: How to use document() of doc() function with copy idiom, or how to acc
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 25 Jul 2006 16:40:31 +0100
Re:  How to use document() of doc() function with copy
> I replaced it with <xsl:copy-of select="doc(xxx)" /> and now it works.

It works, but it's very expensive on memory. You end up with two copies
of your input document in memory, the first one, loaded with doc() and
a second new document  stored in $documents that has a different
structure and _copies_ of all the nodes of the first.

It's not clear why you need to wrap your source document in a new <doc>
element before applying templates, if instead you wrnt

<xsl:variable name="document" select="document($input-file)"/>

then $document would be the (original) document node.
You would then just generate the <doc> element on output, 

    <xsl:template name="main" match="/">
                <input-filename><xsl:value-of select="." /></input-filename>
                <xsl:apply-templates select="$document/*" mode="copy" />

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