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RE: xslt and JSP 1.2

Subject: RE: xslt and JSP 1.2
From: "Bryan Rasmussen" <bry@xxxxxxxxxx>
Date: Fri, 11 Jan 2002 10:30:19 +0100
xsl output jsp
you mean you don't want the xml declaration, use <xsl:output method="xml"
omit-xml-declaration="yes"/> is one solution, should also be able to say
<xsl:output method="jsp"/>, try one of these as a child of xsl:stylesheet

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
Sent: 10. januar 2002 21:04
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  xslt and JSP 1.2

Hello everyone,

I am trying to output JSP 1.2 from a stylesheet. I am stumbling on one
issue. I am sure it is user error but can not figure out what is going on.
My transformation works fine if I just output html code. However, if I try
to output JSP 1.2 the resulting page wants to add the xml document that the
transform was done on to the top of the output page.See below. Any

<?xml version="1.0" encoding="UTF-8"?>
<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version
parameter</title></head><body><h2>XML source</h2><p>Hello</p><h2>Stylesheet
parameter</h2><p>The param1 stylesheet parameter has been set to default


<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version
  <xsl:param name="param1" select="'default value'"/>
     <xsl:template match="/">
     <jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="1.2">

      <head><title>Stylesheet parameter</title></head>
        <h2>XML source</h2>
          <p><xsl:value-of select="."/></p>
        <h2>Stylesheet parameter</h2>
          <p>The param1 stylesheet parameter has been set to <xsl:value-of



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