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Re: collapsing consecutive elements

Subject: Re: collapsing consecutive elements
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Fri, 18 Jan 2002 13:45:20 -0500
xsl find consecutive elements
At 2002-01-18 12:50 -0500, Saverio Perugini wrote:
Does anyone know of a quick and dirty way to collapse a series of
elements which each have only one child?
The following stylesheet is close, but not quite there yet.

You will find the example below shorter than your intermediate answer.

I hope this helps.

............. Ken

T:\ftemp>type saverio.xml <db> <a> <b> <c> <d/> <e/> </c> </b> </a>


T:\ftemp>type saverio.xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

<xsl:output indent="yes"/>

<xsl:template match="*">

<xsl:template match="*[count(*)=1]"><!--first with one child-->
  <xsl:apply-templates mode="one-child"/>

                        <!--child of last one with one child-->
<xsl:template match="*[count(*)!=1]" mode="one-child">
  <xsl:variable name="container-name">
    <xsl:for-each select=".|ancestor::*[count(*)=1]">
      <xsl:if test="position()>1">_</xsl:if>
      <xsl:value-of select="name(.)"/>
  <xsl:element name="{$container-name}">

<xsl:template match="text()" mode="one-child"/>


T:\ftemp>saxon saverio.xml saverio.xsl
<?xml version="1.0" encoding="utf-8"?>










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