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RE: for-each question/IE5

Subject: RE: for-each question/IE5
From: "Pettigrew, Nancy" <NancyPettigrew@xxxxxxxxxxxxx>
Date: Wed, 26 Jan 2000 14:36:34 -0800
nancy pettigrew
EXCELLENT.  It worked.  Kudos and many thanks to Ben.

Sol'n:
<SELECT size="10" multiple="multiple">
<xsl:for-each select="/MCRoot/Lists/Languages/Language">
   <option>
	<xsl:if test="/MCRoot/Person/Languages/Language[@value
=context()/@value]">
		<xsl:attribute name="selected">selected</xsl:attribute>
	</xsl:if>
   <xsl:value-of select="@value"/>
   </option>
</xsl:for-each>
</SELECT>

---------------------------------------------------------
Date: Tue, 25 Jan 2000 18:35:12 -0000
From: Ben Robb <Ben@xxxxxxxxxx>
Subject: RE: for-each question/IE5

Try something like:

++++++++++++++++++++++++++++

<xsl:for-each select="/MCRoot/Lists/Languages/Language">
   <option>
	<xsl:if test="/MCRoot/Lists/Person/Languages[@value =
context()/@value]">
		<xsl:attribute name="selected">selected</xsl:attribute>
	</xsl:if>
   <xsl:value-of select="@value"/>
   </option>
</xsl:for-each>

++++++++++++++++++++++++++++

<warning>this code was lifted and amended from something I wrote about a
year ago - so no guarantees that it works...*grin*</warning>

Hope it helps - as you can see, if using IE5, the only "nice" way of doing
it is by using the context() function.



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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