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RE: position() of the parent

Subject: RE: position() of the parent
From: "Pawson, David" <DPawson@xxxxxxxxxxx>
Date: Thu, 20 Jan 2000 11:45:25 -0000
parent david
DSSSL permits an absolute node numbering relative to the
document root.

Is that achievable in XPATH?

DaveP

>> Worked great! But just for my curiosity, is there any way to find the
>> position() of the parent? 
>
>the question is not well formed. Nodes do not, of themselves, have a
>position, they only have a position in a node list.
>
>So for example if you select the parent with .. or parent:: the
>position() will be 1, as it will be the first node in a list 
>of one, but
>I assume this isn't what you meant.
>
>If you mean what is 1 more than the number of  preceding 
>siblings of the
>parent, you can do
>
>select="1+count(../preceding-sibling::*)"
>
>David
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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