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Re: XML Schema - How to define any element of type Foe

  • From: Michael Kay <mike@saxonica.com>
  • To: cmarchand@oxiane.com
  • Date: Thu, 9 Mar 2017 10:46:47 +0000

Re:  XML Schema - How to define any element of type Foe
It would be nice if XSD allowed a type to be specified on a wildcard, but sadly it doesn't. I can't think of any good reason why not.

Michael Kay

> On 9 Mar 2017, at 09:07, cmarchand@oxiane.com wrote:
> Hello,
> I have a complexType definition, Foe.
> In another complexType, I want to allow any child element, but require that each child element is valid against Foe definition.
> Something like :
> <xs:complexType name="Foe">
>  <xs:attribute name="start" type="xs:positiveInteger" use="required"/>
>  <xs:attribute name="end" type="xs:positiveInteger" use="required"/>
>  <xs:assert test="@end ge @start">
> </xs:complexType>
> <xs:complexType name="parent">
>  <xs:sequence>
>    <xs:any type="Foe"/>
>  </xs:sequence>
> </xs:complexType>
> How can I do this ?
> Thanks,
> Christophe
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