[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: Problem with sorting data within an xml using XSL

• From: Wayne Steele <xmlmaster@h...>
• To: desimonp@i..., xml-dev@x...
• Date: Tue, 03 Oct 2000 14:10:27 -0700 (PDT)

Peter:

   Step 1: can you perform any XSLT transform on an XML document?

   Your method call:

      var newXML = OriginalXML.transferNode("xslfile.XMLDocument");

   is not going to work. Try this first:

      alert( OriginalXML.transformNode(XSLdocument) );

   Once you get this to work, you can worry about

      step 2: can you put the result of an XSLT tranform into a new XML 
document, and
      step 3: how can I get this to sort right?

-Wayne Steele



>From: desimonp@i...
>To: xml-dev@x...
>Subject: Problem with sorting data within an xml using XSL
>Date: Sun, 01 Oct 2000 18:30:27 -0400 (EDT)
>
>
> > Say I have the following:
> > <xml id="OriginalXML">
> > <root>
> >     <Sub_Root_Node>
> >         <Row field1="value1" field2="value2" />
> >         <Row field1="value1" field2="value2" />
> >         <Row field1="value1" field2="value2" />
> >         <Row field1="value1" field2="value2" />
> >         <Row field1="value1" field2="value2" />
> >         <Row field1="value1" field2="value2" />
> >     </Sub_Root_Node>
> > </root>
> > </xml>
> > <xml id="xslfile" src="filexsl.xsl"></xml>
> >
> > I want to rebuild the XML, but have it sorted based field1, if it wasn't
> > sorted at all or it was sorted on field2.  What am I missing?  I am 
>using:
> > var newXML = OriginalXML.transferNode("xslfile.XMLDocument");
> >
> > newXML is blank and newXML.xml is undefined...
> >
> > I tried the following:  fileXSL.xsl
> >
> > <?xml version="1.0"?>
> > <xsl:output method="xml"/>,
> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
> >   <xsl:template match="/">
> > <root>
> >   <Sub_Root_Node>
> >     <xsl:apply-templates select="Sub_Root_Node" />
> >   </Sub_Root_Node>
> > </root>
> >   </xsl:template>
> >   <xsl:template match="Sub_Root_Node">
> >       <xsl:for-each select="Row" order-by="lmfLateDateCount">
> >   <Row
> >    field1="<xsl:value-of select="@field1" />"
> >    field2="<xsl:value-of select="@field2" />"
> >   />
> >       </xsl:for-each>
> >   </xsl:template>
> > </xsl:stylesheet>
> >
> > Peter

_________________________________________________________________________
Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com.

Share information about yourself, create your own public profile at 
http://profiles.msn.com.

• Prev by Date: RE: Who will maintain SAX?
• Next by Date: Re: expanding parameters in DTDs
• Previous by thread: Open Source XML/Java Portal
• Next by thread: Re: XML Schemas: Best Practices
• Index(es):
  • Date
  • Thread