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Topic

Suriya Simsuwat

Subject: Copy element without namespace
Author: Suriya Simsuwat
Date: 11 Jan 2008 02:59 AM

Hi again,

I have one more question to inquiry from you guys that if I want to want to use XSLT copying from xml containing namespace to a new xml without namespace. How can I do it. I have written XSLT for this routine, but it still did not work as what I want yet, so can anyone give me some suggestion to work through it. Thank you in advance.

Source XML file.

<?xml version="1.0"?>
<order xmlns="http://test.com/OrderAdd" name="OrderAdd">
<orderheader>
<name>Jame</name>
<surname>Cool</surname>
<product>
<id>001</id>
<name>book</name>
<qty>3</qty>
</product>
<shiptoaddress>
<name>John Good</name>
<name>IT company</name>
</shiptoaddress>
</orderheader>
</order>

Existing XSLT file.

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://test.com/OrderAdd">

<xsl:template match="t:order">
<gapi>
<xsl:apply-templates/>
</gapi>
</xsl:template>

<xsl:template match="t:*">
<orderheader>
<xsl:copy-of select="@*|node()" />
</orderheader>
</xsl:template>

</xsl:stylesheet>

Current result.

<?xml version="1.0" encoding="UTF-8"?>
<gapi xmlns:t="http://test.com/OrderAdd">
<orderheader>
<name xmlns="http://test.com/OrderAdd">Jame</name>
<surname xmlns="http://test.com/OrderAdd">Cool</surname>
<product xmlns="http://test.com/OrderAdd">
<id>001</id>
<name>book</name>
<qty>3</qty>
</product>
<shiptoaddress xmlns="http://test.com/OrderAdd">
<name>John Good</name>
<name>IT company</name>
</shiptoaddress>
</orderheader>
</gapi>

how to make to the following result?

<?xml version="1.0" encoding="UTF-8"?>
<gapi xmlns="http://test.com/OrderAdd">
<orderheader>
<name>Jame</name>
<surname>Cool</surname>
<product>
<id>001</id>
<name>book</name>
<qty>3</qty>
</product>
<shiptoaddress>
<name>John Good</name>
<name>IT company</name>
</shiptoaddress>
</orderheader>
</gapi>

Ramon Aldana

Subject: Copy element without namespace
Author: Ramon Aldana
Date: 11 Jan 2008 03:50 AM

I use this.

<xsl:output method="text" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>

Suriya Simsuwat

Subject: Copy element without namespace
Author: Suriya Simsuwat
Date: 11 Jan 2008 04:09 AM

Thanks Ramon. Although I tried the code below, it still did not work for my case. I still got the same result as before.

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://test.com/OrderAdd">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="t:order">
<gapi>
<xsl:apply-templates/>
</gapi>
</xsl:template>

<xsl:template match="t:*">
<orderheader>
<xsl:copy-of select="@*|node()" />
</orderheader>
</xsl:template>

</xsl:stylesheet>

(Deleted User)

Subject: Copy element without namespace
Author: (Deleted User)
Date: 11 Jan 2008 09:41 AM

You are not building an output "without namespace", you are writing it in the same namespace of the input.
You should add a xmlns="...." declaration to your XSLT stylesheet, so that gapi ends up in the correct namespace.

Alberto

James Durning

Subject: Copy element without namespace
Author: James Durning
Date: 14 Jan 2008 03:09 PM

For reference for anyone searching this forum:

In your stylesheet node add the following: exclude-result-prefixes="t"
Change your recursive template to use apply-templates instead of copy-of, except for attributes which you still copy.
Declare elements dynamically, using <xsl:element> and local-name() function encased in braces.
Code: ( xml )
<xsl:element name="{local-name()}">
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:element>

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