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Joshua Hunt

Subject: Transform values into elements and then assign values to new elements
Author: Joshua Hunt
Date: 08 Jan 2008 07:24 PM

Hi there,

I need to transform the following XML doc:

<data>
<headers>
<column>title</column>
<column>author</column>
</headers>
<values>
<column>a book</column>
<column>an author</column>
</values>
</data>

Into the format below:

<data>
<title>a book</title>
<author>an author</author>
</data>

Basically, I need each value in <headers> to become an element and then have a value from <values> assigned to it. There will always be as many <headers> values as there are <values> values. Association would be each <headers> column needs to be tied up with each <values> column in turn.

Hopefully this makes sense.

I have tried various solutions, but none of them have come close so far.

Thank you for any help you can provide.

Josh

Joshua Hunt

Subject: Updated: Transform values into elements and then assign values to new elements
Author: Joshua Hunt
Date: 09 Jan 2008 12:53 AM
Originally Posted: 08 Jan 2008 11:30 PM

I am closer to a solution, but need help on the home stretch. I am new to this stuff, so go easy on me. It seems that the following can be done with a two phase approach using temporary trees, but I am constrained to XSLT 1.0 and this is only available in 2.0. Any workarounds would be greatly appreciated. Prefereably one that doesn't require writing an XML doc to file.

I have the following xml doc:

<data>
<headers>
<column>title</column>
<column>author</column>
</headers>
<values>
<column>a book</column>
<column>an author</column>
</values>
</data>

I have added id attributes using the following xslt:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:variable name="headers" select="*"/>
<xsl:template match="/">
<data>
<headers>
<xsl:for-each select="/data/headers/column">
<xsl:element name="column">
<xsl:attribute name="id"><xsl:value-of select="position()"/></xsl:attribute>
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</headers>
<values>
<xsl:for-each select="/data/values/column">
<xsl:element name="column">
<xsl:attribute name="id"><xsl:value-of select="position()"/></xsl:attribute>
<xsl:value-of select="."/>
</xsl:element>
</xsl:for-each>
</values>
</data>
</xsl:template>
</xsl:stylesheet>

This results in the following:

<?xml version="1.0" encoding="UTF-8"?>
<data>
<headers>
<column id="1">title</column>
<column id="2">author</column>
</headers>
<values>
<column id="1">a book</column>
<column id="2">an author</column>
</values>
</data>

From there I use the following XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>

<xsl:variable name="headers" select="*"/>

<xsl:template match="@* | node()">
<xsl:apply-templates select="@* | node()"/>
</xsl:template>

<xsl:template match="/data/values/column">
<xsl:variable name="index" select="@id"/>
<xsl:variable name="newelement" select="$headers/headers/column[@id =$index]"/>
<xsl:element name="{$newelement}">
<xsl:value-of select="."/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

And this gives me exactly what I need:

<?xml version="1.0" encoding="UTF-8"?>
<title>a book</title>
<author>an author</author>

I really need to do this with a single XSLT. Can someone help me integrate the 2 stylesheets into a single one?

Thanks,

Josh

(Deleted User)

Subject: Updated: Transform values into elements and then assign values to new elements
Author: (Deleted User)
Date: 09 Jan 2008 05:19 AM

Hi Joshua,
if your XML only contains one set of "headers" and "values", this should work:

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<data>
<xsl:for-each select="data/headers/column">
<xsl:variable name="pos" select="position()"/>
<xsl:element name="{.}">
<xsl:value-of select="/data/values/column[position()=$pos]"/>
</xsl:element>
</xsl:for-each>
</data>
</xsl:template>

</xsl:stylesheet>

Alberto

Joshua Hunt

Subject: Thank you
Author: Joshua Hunt
Date: 09 Jan 2008 05:33 PM

Thankyou Alberto. That works perfectly.

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