[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: compare two node sets
On Mon, Jan 20, 2020 at 2:19 AM Michael Kay mike@xxxxxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > The simplest (XPath 2.0) solution that comes to mind is > > count(//director) eq count(//author) and > every $d in //director satisfies > some $a in //author satisfies > deep-equal($d/*, $a/*) > +1 (with the improvisation suggested by Martin) -- Regards, Mukul Gandhi http://member.acm.org/~mukulgandhi
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