Re: Need help sorting groups

Thanks Martin!

      From: "Martin Honnen martin.honnen@xxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
 Sent: Monday, January 9, 2017 9:37 AM
 Subject: Re:  Need help sorting groups

On 09.01.2017 15:25, Steve Wisniewski stevewiz76@xxxxxxxxx wrote:

> My question is, how can I sort the groups so that they are sorted in
> value order like this:
>
> <table>
> <thead>
> <tr>
> <th>Range</th>
> <th>Total Value</th>
> </tr>
> </thead>
> <tbody>
> <tr>
> <td>3-6</td>
> <td>$16,500</td>
> </tr>
> <tr>
> <td>7-10</td>
> <td>$7,000</td>
> </tr>
> <tr>
> <td>1-2</td>
> <td>$3,000</td>
> </tr>
> </tbody>
> </table>
>
> I understand how to sort within a group but cannot figure out how to
> solve this issue.


you can store the result in a variable and then sort it

B  B  B  B  B  B  B  <xsl:variable name="rows" as="element(tr)*">
B  B  B B B  B B B  B B B  <xsl:for-each-group
select="location[(xs:integer(class) eq 1) or
(xs:integer(class) eq 2)]" group-by="city">
B B B  B B B  B B B  B B B  B B B  <tr>
B B B  B B B  B B B  B B B  B B B  B B B  <td>1-2</td>
B B B  B B B  B B B  B B B  B B B  B B B  <td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
B B B  B B B  B B B  B B B  B B B  </tr>
B B B  B B B  B B B  B B B  </xsl:for-each-group>
B B B  B B B  B B B  B B B  <xsl:for-each-group
select="location[(xs:integer(class) gt 2) and
(xs:integer(class) lt 7)]" group-by="city">
B B B  B B B  B B B  B B B  B B B  <tr>
B B B  B B B  B B B  B B B  B B B  B B B  <td>3-6</td>
B B B  B B B  B B B  B B B  B B B  B B B  <td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
B B B  B B B  B B B  B B B  B B B  </tr>
B B B  B B B  B B B  B B B  </xsl:for-each-group>
B B B  B B B  B B B  B B B  <xsl:for-each-group
select="location[xs:integer(class) gt 6]"
group-by="city">
B B B  B B B  B B B  B B B  B B B  <tr>
B B B  B B B  B B B  B B B  B B B  B B B  <td>7-10</td>
B B B  B B B  B B B  B B B  B B B  B B B  <td><xsl:value-of
select="format-number(sum(current-group()/value),'$###,###')"/></td>
B B B  B B B  B B B  B B B  B B B  </tr>
B B B  B B B  B B B  B B B  </xsl:for-each-group>
B  B  B  B  B  B  B  </xsl:variable>
B  B  B  B  B  B  B  <xsl:perform-sort select="$rows">
B  B  B  B  B  B  B  B  B  <xsl:sort select="xs:decimal(replace(td[2], '[,$]',
''))" order="descending"/>
B  B  B  B  B  B  B  </xsl:perform-sort>

Having to do the replace after the formatting is probably not the right
approach but you could in the first step only store the number values
and in the second step sort and format if wanted.