Re: with XPath 1.0, select all following sibling eleme

Thanks again!
Wolfhart

Would something like the following work for you?

B  following-sibling::foo intersect
B  following-sibling::*[not(self::foo)][1]/preceding-sibling::foo

. . . . . . . Ken

At 2021-02-18 01:32 +0000, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx wrote:

Content-Transfer-Encoding: 8bit

Dear list,

I am facing an XPath problem for which I cannot find the solution. I want to select all following sibling elements of name "foo" up to the first non-"foo" element. So, in the following case, the first two <foo> elements should be selected:

<foo/>
<foo/>
<bar/>
<foo/>

In the following case, all three <foo> elements should be selected:

<foo/>
<foo/>
<foo/>

And in the following case, nothing should be selected:

<bar/>
<foo/>
<foo/>

I came up with the following non-working approach:

B B B B B B B B B B B <xsl:choose>
B B B B B B B B B B B B B B B <xsl:when test="not(following-sibling::*[not(self::foo)])">
B B B B B B B B B B B B B B B B B B B <xsl:value-of select="following-sibling::*"/>
B B B B B B B B B B B B B B B </xsl:when>
B B B B B B B B B B B B B B B <xsl:otherwise>
B B B B B B B B B B B B B B B B B B B <xsl:value-of select="following-sibling::*[not(self::source)][1]/preceding-sibling::*[self::source][preceding-sibling::current()]"/>
B B B B B B B B B B B B B B B </xsl:otherwise>
B B B B B B B B B B B </xsl:choose>

That is, test whether there are non-"foo" following siblings. If there are none, take all following siblings. If there are, go forward to the first non-"foo" sibling, and from there go backwards, taking all the "foo" siblings up to the current node.

But this does not work. Apparently, the expression "preceding-sibling::current()" is not a valid construct. So what is the correct way to do what I have in mind (or a simpler solution, if there is one). Please note that this stylesheet needs to be executed by a web browser, and so the solution has to remain within XPath 1.0.

Thanks in advance for your help!
Wolfhart

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