Re: [saxon] Questions about the `saxon:threads` extens

> A saxon:unordered attribute on the xsl:for-each itself would be much more
robust.

Yes!  This would be a **Great** feature.

Thanks,
Dimitre

On Thu, Jan 2, 2020 at 3:22 PM Michael Kay mike@xxxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>
>
> On 2 Jan 2020, at 22:28, Dimitre Novatchev dnovatchev@xxxxxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> > (1) fn:unordered doesn't relate very well to xsl:for-each because
> functions can't be applied directly to instructions; it would make more
> sense,
> > > I think, to add a saxon:unordered attribute to xsl:for-each.  I don't
> think it's a particularly easy change to make, given the existing code,
> > > though I'm sure it could be done. One question is whether the result
> corresponds to some permutation of the input sequence,
> > > or to some permutation of the output sequence (that is, are the
> multiple result items corresponding to one input item
> > > deliverered in the "correct" order? Getting that right depends on
> understanding the use cases, and I'm not sure I do...
> >
> > In this case we need a permutation of the input sequence.
>
> More precisely, we need fn:unordered($vmultithreadingResults) to produce
> the items in $vmultithreadingResults in the order that they are being
> produced
>
>
> The problem there is that before evaluating the for-each in unordered
> mode, we need to know that all references to the variable don't care about
> ordering. That kind of analysis isn't impossible, but it's also rather
> fragile; you only need to add an xsl:message that prints the contents of
> the variable, and you change the way it's evaluated, with no visibility as
> to why adding diagnostics has changed the result. A saxon:unordered
> attribute on the xsl:for-each itself would be much more robust.
>
> Michael Kay
> Saxonica
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-- 
Cheers,
Dimitre Novatchev
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