[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: accumulators and continuous numbering
On Fri, Oct 18, 2019 at 08:21:28PM -0000, Martin Honnen martin.honnen@xxxxxx scripsit: > On 18.10.2019 21:08, Graydon graydon@xxxxxxxxx wrote: > > Is there a better way to get the single continuous sequence of numbers? > > If don't want to create a result tree then I think instead of > > <xsl:variable as="element(w:document)+" name="numberedSrc"> > <xsl:apply-templates mode="fileNumber" select="$contentSet" /> > </xsl:variable> > > you would need to use xsl:iterate select="$contentSet" and pass the > latest accumulator on as the parameter of xsl:iterate, like I have done > in https://xsltfiddle.liberty-development.net/bwdwrT > > <xsl:variable name="transformed-docs" as="element(root)*"> > <xsl:iterate select="$docs"> > <xsl:param name="sum" as="xs:integer" select="0"/> > <xsl:apply-templates> > <xsl:with-param name="sum" tunnel="yes" select="$sum"/> > </xsl:apply-templates> > <xsl:next-iteration> > <xsl:with-param name="sum" select="$sum + > accumulator-after('acc-example')"/> > </xsl:next-iteration> > </xsl:iterate> > </xsl:variable> > > Not sure whether that is anything better, it seems to be a bit too > complicated. Given the size of what I've got, I'll stick with "let's throw the lot in a container element", but good to have a "by the each" example available. Thank you! Graydon
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