Re: Need an XPath 2.0 expression that identifies a lon

On Mon, Oct 14, 2019 at 10:38 PM Costello, Roger L. costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> I came up with this XPath expression:
>
> //p[o:p eq '&#160;'][count(following-sibling::*[position() le 10][name()
> eq 'p'][o:p eq '&#160;']) ge 10][1]
>
> It says, "Give me the first <p> element containing a non-blocking space
> character such that there are at least 10 <p> elements that immediately
> follow it, each containing a non-blocking space character." At least,
> that's what I think it says. Note: 10 is an arbitrary number.
>
> 1. Do you see any problems with the XPath expression?
>

I think that, your XPath expression should be following,

//p[o:p eq '&#160;'][count(following-sibling::*[name() eq 'p'][o:p eq
'&#160;']) ge 10][1]

(not tested)

The predicate [position() le 10] occurring for the first time in your
expression, doesn't seem to be needed.


> 2. Is there a better XPath expression?
>

I could visually inspect / review Mike Kay's expression, and can say that
its correct.



-- 
Regards,
Mukul Gandhi