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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XSLT 2: Best Way to Synthesize Elements Given List
I'd suggest this non-recursive solution:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:param name="pPath" select="'/foo/bar/baz/bam/bak/bap/bah/baw'"/>
<xsl:variable name="vNames" select="tokenize($pPath, '/')[.]"/>
<xsl:template match="*[count(current()/ancestor::*) lt count($vNames)]">
<xsl:element name="{$vNames[count(current()/ancestor::node())]}">
<xsl:apply-templates select="*"/>
</xsl:element>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
When applied on:
<x1>
<x2>
<x3>
<x4>
<x5>
<x6>
<x7>
<x8>
<x9>
<x10>
<x11>
<x12>
<x13>
<x14>
<x15>
<x16>
<x17>
<x18>
<x19>
<x20>
</x20>
</x19>
</x18>
</x17>
</x16>
</x15>
</x14>
</x13>
</x12>
</x11>
</x10>
</x9>
</x8>
</x7>
</x6>
</x5>
</x4>
</x3>
</x2>
</x1>
the result is:
<foo>
<bar>
<baz>
<bam>
<bak>
<bap>
<bah>
<baw/>
</bah>
</bap>
</bak>
</bam>
</baz>
</bar>
</foo>
Cheers,
Dimitre
On Sat, Nov 5, 2016 at 9:18 AM, Eliot Kimber ekimber@xxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> Say I have this string: "foo/bar" (or any arbitrarily-long sequence of
> /-delimited tag names) and want to construct from it:
>
> <foo>
> <bar>
> <!-- Stuff added here that I get from somewhere else -->
> </bar>
> </foo>
>
> Is there an easier or more obvious way to generate this than an recursive
> function?
>
> With a recursive function I can easily create child elements until the
> sequence is exhausted but it feels like there should be an easier way
> using XSLT 2 but if there is I'm not thinking of it.
>
> Cheers,
>
> Eliot
>
> --
> Eliot Kimber
> http://contrext.com
>
>
>
>
>
--
Cheers,
Dimitre Novatchev
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biggest mistake of all
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write all patents, too? :)
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I finally figured out the only reason to be alive is to enjoy it.
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