Re: Doing Math on Durations and Creating dayTimeDurati

A lot of people miss this one. By providing a convenient operator for this
common operation, we ensured that people searching the function library
wouldn't find it...

Michael Kay
Saxonica

> On 6 Oct 2016, at 13:37, Eliot Kimber ekimber@xxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> I think that's what I missed: I didn't realize you could do arithmetic
> that directly.
>
> I'll try it.
>
> Cheers,
>
> Eliot
> --
> Eliot Kimber
> http://contrext.com
>
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> On 10/6/16, 12:24 PM, "Jirka Kosek jirka@xxxxxxxx"
> <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
>> On Thu, Oct 6, 2016, at 11:40, Eliot Kimber ekimber@xxxxxxxxxxxx wrote:
>>> I'm using XSLT to extract timing information from logs in order to
>>> determine the duration of actions. Each log item has a time stamp in the
>>> usual format (2016-10-05T15:52:17.525:+0200).
>>
>> And why are you simply not just subtracting two dateTimes, something
>> like:
>>
>> xs:dateTime("2015-01-01T12:00:00Z") -
>> xs:dateTime("2014-07-10T12:00:00Z")
>>
>> This will give you back duration. Or perhaps I have misunderstood...
>>
>> Jirka
>>
>> --
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