Re: Only child test

Wouldn't "last() eq 1" or "last() gt 1" be both the fastest and clearest?
ac

../*[2]

This is the  first expression I thought about -- then saw that
PQQP5Q
P;P0P2 P!P5P4P>P2 has already offered it.

Cheers,
Dimitre

On Wed, Oct 9, 2013 at 9:38 PM, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote:

Just curious how other's might approach a test to determine if the
current node is *not* an only child. This works fine but it feels a
little heavy to me.  Thoughts?

                 <xsl:if test="(count(preceding-sibling::*) +
count(following-sibling::*)) &gt; 1">
                     <hr/>
                 </xsl:if>