[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Only child test
../*[2] This is the first expression I thought about -- then saw that PQQP5QP;P0P2 P!P5P4P>P2 has already offered it. Cheers, Dimitre On Wed, Oct 9, 2013 at 9:38 PM, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote: > Just curious how other's might approach a test to determine if the > current node is *not* an only child. This works fine but it feels a > little heavy to me. Thoughts? > > <xsl:if test="(count(preceding-sibling::*) + > count(following-sibling::*)) > 1"> > <hr/> > </xsl:if> > -- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- Never fight an inanimate object ------------------------------------- To avoid situations in which you might make mistakes may be the biggest mistake of all ------------------------------------ Quality means doing it right when no one is looking. ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play ------------------------------------- Facts do not cease to exist because they are ignored. ------------------------------------- Typing monkeys will write all Shakespeare's works in 200yrs.Will they write all patents, too? :) ------------------------------------- I finally figured out the only reason to be alive is to enjoy it.
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