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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Combining of nested children
 Thanks for your suggestions. As you can see, the requirements are a bit more complex than in the example I sent Here is the code I worked out that works for <Heading> but not at the nested <SubDiv1> level. I get a "multiple-argument for concat" at the second level in this template. I suspect I am doing something stupid, but not sure what the arguments of the second for-each-group should be. Mark <xsl:param name=" sorting-collation" select="'http://www.w3.org/2005/xpath-functions/collation/codepoint'"/> <!--<xsl:param name=" sorting-collation" select="'http://saxon.sf.net/collation?class=CzechCollation'"/>--> <xsl:template match="List"> <List> <!-- Group by Heading --> <!-- The ' ' separator between Heading and Heading/@entry insures proper sorting --> <xsl:for-each-group select="Item" group-by="concat(Heading/@data, Heading/@catalog, Heading/@scott-number, Heading/@pofis-number,' ',Heading/@entry) " collation="{$sorting-collation}"> <xsl:sort select="current-grouping-key()" collation="{$sorting-collation}"/> <Item> <Heading> <xsl:copy-of select="current-group()/Heading/@*"/> <xsl:copy-of select="current-group()/Heading/ToRef"/> <xsl:copy-of select="current-group()/Heading/Article"/> <!-- <xsl:copy-of select="Heading/SubDiv1"/> Ignore this line it substitutes for the code below without inserting the <ToRef>--> <!-- This is failing <xsl:for-each-group select="current-group()" group-by="concat(Heading/SubDiv1/@data, Heading/SubDiv1/@catalog, Heading/SubDiv1/@scott-number, Heading/SubDiv1/@pofis-number)"> <xsl:sort select="current-grouping-key()" collation="{$sorting-collation}"/> <xsl:if test="Heading/SubDiv1"> <xsl:element name="SubDiv1"> <xsl:copy-of select="current()/Heading/SubDiv1/@*"/> <xsl:copy-of select="current-group()/Heading/SubDiv1/ToRef"/> <xsl:copy-of select="current-group()/Heading/SubDiv1/Article"/> <xsl:copy-of select="Heading/SubDiv1/SubDiv2"/> </xsl:element> </xsl:if> </xsl:for-each-group> --> </Heading> </Item> </xsl:for-each-group> </List> </xsl:template> -----Original Message----- From: Syd Bauman Sent: Wednesday, September 05, 2012 9:28 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Combining of nested children Not sure I understand the requirements completely, but given your input, the following does produce the desired output. --------- <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <!-- standard easy-to-write identity template -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template><!-- process a heading that has an @id specially: --> <xsl:template match="Heading[@id]"> <xsl:copy> <!-- first, process my attributes --> <xsl:apply-templates select="@*"/> <!-- then, copy over desired <ToRef> --> <xsl:apply-templates select="../../Item/Heading[ not(@id) and @entry = current()/@entry and @data eq current()/@data ]/ToRef"/> <!-- last, process my children --> <xsl:apply-templates select="node()"/> </xsl:copy> </xsl:template> <!-- ignore <Item>s that have <Heading>s from which we already took the <ToRef> --> <!-- (Note that this code does not check to see that we actually took or will --> <!-- take the <ToRef> ? rather it just tests if there is no id= attr, and figures --> <!-- that if there is not an id=, then the entry= and data= must have matched. --> <xsl:template match="Item[Heading[not(@id)]]"/> </xsl:stylesheet> --------- I need to find <Items> in a <List> that have an identical <Heading> attributes except for the @id, and insert a <ToRefs> element from the <Item> without an @id into the <Item> that has the @id attribute. Sample input and output <Item>s are shown below. Input: Output: 
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