[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: copying namespaces question
For the ones interested ... I wrote an article explaining 2 approaches used to solve the problem: http://robbypelssers.blogspot.nl/2012/07/splitting-xml-content-into-multiple. html Thx for the help !! Robby -----Original Message----- From: Robby Pelssers [mailto:Robby.Pelssers@xxxxxxx] Sent: Monday, July 02, 2012 12:53 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: copying namespaces question It seems like great minds think alike !! ;-) Thx a lot (again)... !!!! Robby -----Original Message----- From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx] Sent: Monday, July 02, 2012 12:50 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: copying namespaces question On 2 July 2012 11:40, Michael Kay <mike@xxxxxxxxxxxx> wrote: > I think I would do it like this: bah, as I was typing it out.... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output indent="yes"/> <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* ,node()"/> </xsl:copy> </xsl:template> <xsl:template match="/"> <xsl:for-each select="//*:object"> <xsl:result-document href="path/to/{*:name}.xml"> <xsl:apply-templates select="root(.)/*"> <xsl:with-param name="current-object" select="." tunnel="yes"/> </xsl:apply-templates> </xsl:result-document> </xsl:for-each> </xsl:template> <xsl:template match="*:object"> <xsl:param name="current-object" tunnel="yes"/> <xsl:if test=". is $current-object"> <xsl:copy> <xsl:apply-templates select="@*, node()"/> </xsl:copy> </xsl:if> </xsl:template> </xsl:stylesheet> -- Andrew Welch http://andrewjwelch.com
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|