RE: why does the linit not work here ?

Thanks but it won't work.



When I change it to this : <xsl:apply-templates
select="dagboek/entry[[position() &gt; $offset and position() &lt; $end]
 " />




I see this error message :



XSLTProcessor::importStylesheet():



Invalid expressionXSLTProcessor::importStylesheet(): XSLT-apply-templates:
could not compile select expression 'dagboek/entry[[position() > $offset and
position() < $end]

XSLTProcessor::transformToXml(): No stylesheet associated to this object



Roelof







---------------------------------------- > Date: Fri, 13 Jan 2012 13:50:27
-0500 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx; xsl-list@xxxxxxxxxxxxxxxxxxxxxx >
From: gkholman@xxxxxxxxxxxxxxxxxxxx > Subject: Re:  why does the linit
not work here ? > > At 2012-01-13 18:45 +0000, Roelof Wobben wrote: > >What i
was expecting was if I goto page 2 of april 2005 there will > >be 3 articles
displayed because articles_per_page has the value of 3 > >and offset has value
of 1 and end has the value of 5. > > > >So this rule : >the articles between 1
and 5. So articles 2,3,4. > > But it won't because the second predicate is
applied to the *results* > of the first predicate. To have it applied
simultaneously with the > first predicate, you need to put it *in* the first
predicate: > > [position() > $offset and position() < $end] > > >Can anyone
help me figure out why this happens ? > > Because the "[position() < $end]"
predicate is being applied to > those returned by the "[position() > $offset]"
predicate. > > I hope this helps. > > . . . . . . . . Ken > > > -- > Contact
us for world-wide XML consulting and instructor-led training > Free 5-hour
video lecture: XSLT/XPath 1.0 & 2.0 http://ude.my/uoui9h > Crane Softwrights
Ltd. http://www.CraneSoftwrights.com/s/ > G. Ken Holman
mailto:gkholman@xxxxxxxxxxxxxxxxxxxx > Google+ profile:
https://plus.google.com/116832879756988317389/about > Legal business
disclaimers: http://www.CraneSoftwrights.com/legal > > >