Re: Position() Function Using Filter

I am trying to figure out how to get the position of a particular node
after apply a filter. I am able to get the result after using the
XPath below, however, I can't seem to figure out how to get the
position of that node.

bpage = ASTRO_00007.JPG
books/book[substring-after(substring-after(substring-after(text(),
'/'), '/'), '/')=$bpage]

<books>
<book>books/physics/astronomy/ASTRO_00002.JPG</>
<book>books/physics/astronomy/ASTRO_00003.JPG</>
<book>books/physics/astronomy/ASTRO_00004.JPG</>
<book>books/physics/astronomy/ASTRO_00005.JPG</>
<book>books/physics/astronomy/ASTRO_00006.JPG</>
<book>books/physics/astronomy/ASTRO_00007.JPG</>
<book>books/physics/astronomy/ASTRO_00008.JPG</>
<book>books/physics/astronomy/ASTRO_00009.JPG</>
<book>books/physics/astronomy/ASTRO_00010.JPG</>
</books>

  <xsl:number/>
can help to find the "position" of a node relative to other nodes.

	Martin Honnen --- MVP Data Platform Development
	http://msmvps.com/blogs/martin_honnen/