Re: XML text search & replace

Hello

There is a requirement to search for a particular pattern in XML
documents and replace them by reading another XML file and copying
over the replacement text correcpinding to the original text.  I have
been trying to use<xsl:analyze-string>  in xslt 2.0. but I am not sure
how to read another XML file using this tag.

As an example, if I have some text tagged within<para> tags :

<para> this is a simple text</para>

I have an external xml file of the form:

<matchtext>simple</matchtext>
<replacetext>hard</replacetext>

In my<xsl:matching-substring>, can I use doc() to read the external
XML file and replace the text?

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:xsd="http://www.w3.org/2001/XMLSchema"
  exclude-result-prefixes="xsd"
  version="2.0">

  <xsl:template match="para">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="para//text()">
    <xsl:analyze-string select="." regex="{$rep-pattern}">
      <xsl:matching-substring>
        <xsl:value-of select="key('rep-key', ., $rep-doc)/replacetext"/>
      </xsl:matching-substring>
      <xsl:non-matching-substring>
        <xsl:value-of select="."/>
      </xsl:non-matching-substring>
    </xsl:analyze-string>
  </xsl:template>

<replacements>
  <replacement>
    <matchtext>simple</matchtext>
    <replacetext>hard</replacetext>
  </replacement>
</replacements>

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/