[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Accessing the XML file name from an XSL Transform
I need to access the filename (well, actually without the extension, but that's a simple RegEx) in an XSL Transform Obviously, I can pass a xsl:param name= to a XSLT transform that contains the filename, but I can't see how to achieve this when using Saxon's -s: command line option where -s: contains a directory and not a file. I'm sure there's got to be a way to find out the XML doc name that's being transformed, but I just can't find it. Is this possible?
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