Re: Mapping from two sources

Hi, 

does xsl:for-each-group acts like inner join?

Thank you for the
response. 

--- On Fri, 10/1/10, Michael Kay <mike@xxxxxxxxxxxx> wrote:

>
From: Michael Kay <mike@xxxxxxxxxxxx>
> Subject: Re:  Mapping from two
sources
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Date: Friday, October 1, 2010,
5:13 PM
>   On 01/10/2010 8:14 PM,
> sudheshna iyer wrote:
> 
> Grouping
handles this well:
> 
> <xsl:for-each-group select="$doc1//OrderLine,
>
$doc2//POOrderline" 
> group-by="OLN">
> <Oline>
> <OLN><xsl:value-of
>
select="current-grouping-key()"></OLN>
> <xsl:copy-of
select="current-group()/(FName, ID)"/>
> </Oline>
> </xsl:for-each-group>
> 
>
Michael Kay
> Saxonica
> 
> > I need to have two sources:
> >
> > input1 and
input2.
> >
> > input1:
> > <?xml version="1.0" encoding="ISO-8859-1"?>
> >
<Order>
> >     <OrderLine>
> >        
>     <OLN>1</OLN>
> >        
>    
<Fname>aa</Fname>
> >     </OrderLine>
> >     <OrderLine>
> >        
>    
<OLN>2</OLN>
> >        
>     <Fname>bb</Fname>
> >    
> </OrderLine>    
>
> </Order>
> >
> >
> > input2:
> > <?xml version="1.0" encoding="ISO-8859-1"?>
> > <POOrder>
> >     <POOrderLine>
> >        
>     <OLN>1</OLN>
> >        
>     <ID>123</ID>
> >        
>     <LName>aa</LName>
> >     </POOrderLine>
> >     <POOrderLine>
> >        
>     <OLN>2</OLN>
> >        
>    
<ID>324</ID>
> >        
>     <LName>bb</LName>
> >    
> </POOrderLine>   
> > </POOrder>
> >
> > I need the output from both sources combined. Please
>
note that first two elements are coming from input1 and
> thrid element is
from input2. What is the
> > optimal way of doing this?
> >
> > <?xml
version="1.0" encoding="ISO-8859-1"?>
> > <OrderResponse>
> >     <Oline>
> >
       
> <OLN>1</OLN>
> >        
> <Fname>aa</Fname>
> >        
>
<ID>123</ID>
> >     </Oline>
> >     <Oline>
> >        
> <OLN>2</OLN>
> >
       
> <Fname>bb</Fname>
> >        
> <ID>324</ID>
> >     </Oline>
> >
</OrderResponse>
> >
> >
> >
> >
> >
>
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