Re: Recognizing new line character in XSL

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Subject: Re: Recognizing new line character in XSL
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Tue, 20 Jul 2010 12:33:15 +0100

Assuming that you apply-templates to text nodes, and that you are generating HTML, and that you are using XSLT 2.0, you can do

<xsl:apply-template match="text()">
<xsl:for-each select="tokenize(., '\n')">
<p><xsl:value-of select="."/></p>
</
</

Oh, I see you're using XSLT 1.0. That's tedious - in that case you need a recursive named template that uses substring-before to process the text before the first newline, and then calls itself passing substring-after(., '& #xa;') to process the text after the first newline.

Michael Kay
Saxonica

On 20/07/2010 12:13, Siddhi Thakkar wrote:

Hi Experts,
Could you please guide me if there is any way in XSL to recognize new line character and display each line as a new paragraph? I am not sure of the Unicode entity of new line char, if we really need it we can assume it to be&#xa;
I am using JDOM as processor and xsl version 1.0.

Thanks much in advance for help.
Siddhi

Current Thread
Recognizing new line character in XSL Siddhi Thakkar - 20 Jul 2010 11:13:30 -0000 Martin Honnen - 20 Jul 2010 11:21:40 -0000 Michael Kay - 20 Jul 2010 11:33:33 -0000 <= Dimitre Novatchev - 20 Jul 2010 12:47:23 -0000 Hermann Stamm-Wilbrandt - 20 Jul 2010 12:51:03 -0000

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