[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] AW: replaceing chars with entities
works like a charm ! thx a lot ! greetings Patrick Szabo XSLT-Entwickler Tel.: +43 (1) 534 52 - 1573 Fax: +43 (1) 534 52 - 146 Patrick.Szabo@xxxxxxxxxxxxx LexisNexis Verlag ARD Orac GmbH & Co KG Marxergasse 25, 1030 Wien FN 8333f, Handelsgericht Wien http://www.lexisnexis.at/ -----UrsprC<ngliche Nachricht----- Von: Martin Honnen [mailto:Martin.Honnen@xxxxxx] Gesendet: Mittwoch, 02. Juni 2010 14:18 An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Betreff: Re: replaceing chars with entities Szabo, Patrick (LNG-VIE) wrote: > I'm using XSLT 2.0 and Saxon 9 > Im trying to replace certain chars with entities like this: > > <xsl:template match="text()"> > <xsl:value-of select="replace(replace(replace(replace(., 'C', 'ß', 'i'), 'C$', 'ä', 'i'), 'C<', 'ü', 'i'), 'C6', 'ö', 'i')" disable-output-escaping="yes"/> > </xsl:template> > > It just doesn't seem to to anything. If i do this: > > <xsl:template match="text()"/> > > all the text from the document is gone so the template matches...it just doesn't replace anything :-/ > > Any ideas ?! Well in an XML document like an XSLT stylesheet 'ß' is the same as writing 'C' so you are replacing each character with itself with your code. If you want to replace certain characters with numeric character references in the serialized output of an XSLT 2.0 transformation then you can achieve that with a character map: http://www.w3.org/TR/xslt20/#character-maps <xsl:character-map name="map1"> <xsl:output-character character="C" string="&#223;"/> ... </xsl:character-map> <xsl:output use-character-maps="map1"/> -- Martin Honnen http://msmvps.com/blogs/martin_honnen/
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