Re: The output of evaluating an XSLT transform is the

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Subject: Re: The output of evaluating an XSLT transform is the same regardless of the order in which output elements are evaluated. Right?
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 13 Apr 2010 12:40:58 +0100

On 13/04/2010 12:33, Costello, Roger L. wrote:

an be constructed in any order, even in parallel. However, from yesterday's responses, I am more confused than before. Would you (or anyone) please explain how the elements in an XSLT document can be executed in any order, even in parallel?

the XSLT specification doesn't constrain the implementation in any way it just defines the result. So if it is generating a serialised result to a file, it is not forced to generate an in memory result tree, at all, and if it does generate one it can generate the parts of that tree in any order it wants. The only thing that matters is that the final serialised result is as specified. You seem to be looking for some definite statement about the temporal ordering of execution, but that is just a source of confusion. The result is specified in terms of the input, how an actual implementation produces that result isn't specified.

David

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Current Thread

The output of evaluating an XSLT transform is the same regardless of the order in which output elements are evaluated. Right?
- Costello, Roger L. - 12 Apr 2010 17:40:15 -0000
  - David Carlisle - 12 Apr 2010 17:47:15 -0000
  - Michael Kay - 12 Apr 2010 17:53:49 -0000
    - Costello, Roger L. - 13 Apr 2010 11:33:42 -0000
      - David Carlisle - 13 Apr 2010 11:41:19 -0000 <=
      - Syd Bauman - 13 Apr 2010 12:02:59 -0000
      - David Carlisle - 13 Apr 2010 12:14:20 -0000
      - Wendell Piez - 13 Apr 2010 16:06:28 -0000
      - Message not available
      - G. Ken Holman - 13 Apr 2010 11:54:13 -0000

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RE: The output of evaluating , Costello, Roger L.	Thread	Re: The output of evaluating , Syd Bauman
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