Re: EXSLT replace to XSLT 2.0 replace

So either:
    <xsl:value-of select="replace(
                             .,

'(?:(.+@.+\.[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
                            '$1$2$3',
                            '!'
                          )"/>
or:
    <xsl:value-of select="replace(
                             .,

'((.+@.+\.[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))',
                            '$2$3$4'
                          )"/>

Omit the 'g', which replace() does anyway.

Omit the '(?: ... )" from the regular expression. (This is uncounted
grouping, which isn't important here.

The | in  (\p{Lu}|\p{Ll}]  looks suspicious. These are alternatives,
anyway, within []

-W

On Wed, Apr 14, 2010 at 9:48 AM, Szabo, Patrick (LNG-VIE)
<patrick.szabo@xxxxxxxxxxxxx>  wrote:

Hi,

I'm using Saxon 9 and XSLT 2.0

I'm currently updateing a few 1.0 Stylesheets to 2.0.
In one of those Stylesheets i've found this:

<xsl:value-of select="regexp:replace(.,
'(?:(.+@.+\.[a-zA-Z]+)|([\p{Lu}|\p{Ll}]\p{Ll}+)-([\p{Ll}]+))', 'g',
'$1$2$3')"/>

Is there a way to to that in 2.0 without EXSLT ?!
I - of course - wanted to try it with replace() but i cant seem to
figure it out.

best regards...

Patrick Szabo
  XSLT-Entwickler

Tel.: +43 (1) 534 52 - 1573
Fax: +43 (1) 534 52 - 146

Patrick.Szabo@xxxxxxxxxxxxx

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