[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Display more than one table in generic xslt - reg
Ramesh Kumar wrote:
The required HTML output is like.... Here is an XSLT 1.0 stylesheet: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html" indent="yes"/> <xsl:strip-space elements="*"/> <xsl:key name="by-name" match="/*/*" use="concat('{', namespace-uri(), '}', local-name())"/> <xsl:template match="/"> <html> <body> <table> <tbody> <xsl:apply-templates select="*/*[generate-id() = generate-id(key('by-name', concat('{', namespace-uri(), '}', local-name()))[1])]" mode="table"/> </tbody> </table> </body> </html> </xsl:template> <xsl:template match="/*/*" mode="table"> <tr> <td> <table border="1"> <thead> <tr> <xsl:apply-templates mode="th"/> </tr> </thead> <tbody> <xsl:apply-templates select="key('by-name', concat('{', namespace-uri(), '}', local-name()))"/> </tbody> </table> </td> </tr> <xsl:if test="position() != last()"> <tr> <td> </td> </tr> </xsl:if> </xsl:template> <xsl:template match="/*/*/*" mode="th"> <th> <xsl:value-of select="local-name()"/> </th> </xsl:template> <xsl:template match="/*/*"> <tr> <xsl:apply-templates/> </tr> </xsl:template> <xsl:template match="/*/*/*"> <td> <xsl:value-of select="."/> </td> </xsl:template> </xsl:stylesheet> Its output is a bit more structured (using tbody, thead, and th) than your sample but it should give you an idea how to approach that. -- Martin Honnen http://msmvps.com/blogs/martin_honnen/
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|