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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xsl-grouping two different elements together
 i've got another grouping problem. i'm a little stuck where to look for. given the following structure: <?xml version="1.0" encoding="UTF-8"?> <kapitel> <abs>first</abs> <einschub1>first_ein</einschub1> <einschub1>second_ein</einschub1> <leerzeile/> <einschub1>third_ein</einschub1> <abs>second</abs> <einschub2>first_ein2</einschub2> <abs>end</abs> </kapitel> this should transform to: <?xml version="1.0" encoding="UTF-8"?> <kapitel> <abs>first</abs> <einschub typ="1"> <abs>first_ein</abs> <abs>second_ein</abs> <leerzeile/> <abs>third_ein</abs> </einschub> <abs>second</abs> <einschub typ="2"> <abs>first_ein2</abs> </einschub> <abs>end</abs> </kapitel> my current xslt is: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="kapitel"> <xsl:element name="kapitel"> <xsl:for-each-group select="*" group-adjacent="local-name()" > <xsl:choose> <xsl:when test="starts-with(current-grouping-key(),'einschub')"> <xsl:element name="einschub"> <xsl:attribute name="typ" select='replace(local-name(), "[^\d]+", "")'/> <xsl:apply-templates select="current-group()"/> </xsl:element> </xsl:when> <xsl:otherwise> <xsl:apply-templates select="current-group()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each-group> </xsl:element> </xsl:template> <xsl:template match="einschub1|einschub2"> <xsl:element name="abs"> <xsl:apply-templates/> </xsl:element> </xsl:template> </xsl:stylesheet> but this creates two <einschub typ="1"> container. this makes absolutely sense, but i've no idea how to get the <leerzeile> element into the container. my only idea is to make a 2 pass solution: 1. rename all <leerzeile> elements with a template ... <xsl:when test="preceding-sibling::*[1][starts-with(local-name(),'einschub')] and following-sibling::*[1][starts-with(local-name(),'einschub')] "> <xsl:element name="{local-name(preceding-sibling::*[1])}"> ... 2. grouping works. is there any better/more elegant solution? or ideas where to look for? thanks in advance, regards, gregor 
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