[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Display the number of records in a group
Hi, Sorry if i confused you. Let me explain more clearly My xml consists of 11 records , ================================ 123 ABC GOOD 10 123 ABC GOOD 20 123 ABC GOOD 30 456 DEF GOOD 10 789 GHI GOOD 10 567 JKL GOOD 10 234 BCD GOOD 20 345 CDE GOOD 20 678 TTT TRIANGULATION 30 678 TTT TRIANGULATION 20 321 TRT TRIANGULATION 20 ================================ when i used group-by="concat(VAT_TAX_NO,BILL_CUST_NAME,INTRA_EU_TRX_CODE)"> These 11 records are grouping into "8" records. and i want to capture this value and show it in o/p these are the ways i tried.. <xsl:value-of select="count(current-group())"/> giving o/p as <mezo eazon="0A0001D003A">31111121</mezo> <xsl:value-of select="last()"/> giving o/p as <mezo eazon="0A0001D003A">1111111111111111</mezo> <xsl:value-of select="position()"/> giving o/p as <mezo eazon="0A0001D003A">12345678</mezo> expected o/p <mezo eazon="0A0001D003A">8</mezo> Thanks Anil On Mon, Mar 8, 2010 at 6:46 PM, David Carlisle <davidc@xxxxxxxxx> wrote: > On 08/03/2010 13:04, anil kumar wrote: >> >> How to show the toatal number of records, >> ima failing to get this by last() >> because iam grouping 11 records into 8 , so the value of last() is >> giving 11 which is in correct >> >> > > I didn't understand that comment, but inside xsl:for-each-group > > <xsl:value-of select="last()"/> gives you the number of groups > > <xsl:value-of select="count(current-group())"/> gives the number of items in > the current group. > > I'm not sure which of these numbers you want. > > David > > > ________________________________________________________________________ > The Numerical Algorithms Group Ltd is a company registered in England > and Wales with company number 1249803. The registered office is: > Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. > > This e-mail has been scanned for all viruses by Star. The service is > powered by MessageLabs. > ________________________________________________________________________
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