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$ xsltproc anil.xsl anil.xml <?xml version="1.0"?> <name>A</name><name>B</name><name>C</name> $ cat anil.xsl <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/">. <xsl:for-each select="/table/rows/row/name"> <xsl:if test="not(. = preceding::name)"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> $ Mit besten Gruessen / Best wishes, Hermann Stamm-Wilbrandt Developer, XML Compiler, L3 WebSphere DataPower SOA Appliances ---------------------------------------------------------------------- IBM Deutschland Research & Development GmbH Vorsitzender des Aufsichtsrats: Martin Jetter Geschaeftsfuehrung: Dirk Wittkopp Sitz der Gesellschaft: Boeblingen Registergericht: Amtsgericht Stuttgart, HRB 243294 Anil Kumar Veeramalli <anil.v@frescoinf To ormatics.com> xsl-list@xxxxxxxxxxxxxxxxxxxxxx cc 02/10/2010 05:42 PM Subject Re: finding out distinct node/values Please respond to xsl-list@xxxxxxxx lberrytech.com Thanks Andrew for your reply. some where in the documentation I read that, distinct-values doesn't support in XSL1.0...is that true? >> >> By passing the attribute "name" as a parameter, I would like to find out the >> all distinct values of name Attribute . i.e A,B and C >> > > distinct-values(//*[name() = $name]) > > > cheers
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