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Re: Functional Programming: How do I convert an xsl:f

Subject: Re: Functional Programming: How do I convert an xsl:for-each loop into a functional style?
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 21 Jan 2010 16:16:35 +0000
Re:  Functional Programming: How do I convert an  xsl:f
On 21/01/2010 16:03, Costello, Roger L. wrote:
Now I get the desired results no matter what order the xsl:when tests are executed. Thus, I conclude, this xsl:choose is written in a functional style. Do you agree?

No not at all. the comment about changing order (which at best is a hint about what declarative programming is about) does not extend to changing the semantics of the programming language. The order of execution of when clauses is specified. just as if you use nested if then else expressions.


the two versions you post are entirely equivalent except that the second one has an extra superfluous test and (Number le 20) that has no effect 9and may even be removed by an optimizer if it is smart enough)

David

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