[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Copy the Document Type Definition of XML file
Hi!
I'm trying to copy resp. to modify an XML document via XSL. Here I use the usual identity template: <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> Unfortunately the DTD definition of the source document is not copied at this way. Does anybody know how can I accomplish this? The only idea I had was that you can use <xsl:output> to write a DTD declaration. However, I have no idea how I can read out the declaration from the source XML document. Is this possible with XSL? Or should I take e.g. Java and pass the info as a parameter to the stylesheet? Thanks for any suggestions! Rossen K.
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