[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Using outer context node inside for-each
At Wed, 08 Jul 2009 13:42:59 -0400, G. Ken Holman wrote: > > At 2009-07-08 18:31 +0100, Richard Lewis wrote: > >Hi there, > > > >Here is an abstraction of my problem template: > > > > <xsl:template match="record"> > > <xsl:param name="show-fields" /> > > <xsl:variable name="this" select="." /> > > > > <xsl:for-each select="str:tokenize($show-fields)"> > > <xsl:message><xsl:value-of select="$this/field[@name=.]" > > /></xsl:message> > > Inside the predicate "." refers to the node found by the node test. > > You want [@name=current()] to address the context item that is at the > start of the XPath expression. > > Though I see Martin has taken the problem away with a more compact > solution ... still, you wanted to know why yours wasn't working. > > I hope this helps. > Excellent. Works great. Thanks very much for your help. -- -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- Richard Lewis ISMS, Computing Goldsmiths, University of London Tel: +44 (0)20 7078 5134 Skype: richardjlewis JID: ironchicken@xxxxxxxxxxxxxxx http://www.richard-lewis.me.uk/ -=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=- +-------------------------------------------------------+ |Please avoid sending me Word or PowerPoint attachments.| |http://www.gnu.org/philosophy/no-word-attachments.html | +-------------------------------------------------------+
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